An alternate way to define an \(A_{\mathfrak q}(\lambda)\) module is by
specifying a KGB element (attached to the fundamental Cartan), a weight
\(\lambda_q\) to define the \(\theta\)-stable Cartan, and the weight
\(\lambda\) specifying the one-dimensional representation on \(L\).
For this construction, the weight \(\lambda\) must satisfy that
\(\lambda-\rho(\mathfrak u)\) is integral, and of course, it must be
orthogonal to the roots of \(L\).
Let’s look at some examples in \(G=U(2,2)\). A convenient choice for x
is KGB element 2, and we consider \(A_{\mathfrak q}(\lambda)\) modules
attached to a \(\theta\)-stable parabolic with Levi factor
\(U(2,1)\times U(0,1)\):
The function Aq(x,lam,lamq) computes
\(\mathcal R_{\mathfrak q}(\mathbb C_{\lambda})\), but with a different
normalization; there is a shift of \(\rho(\mathfrak u)\) so that the
functor preserves infinitesimal characters: the resulting module shares the
infinitesimal character with the one-dimensional representation
\(\mathbb C_{\lambda}\) of (possibly a double cover of) \(L\). One
advantage of this normalization is that it is easy to see whether
\(\lambda\) is in the weakly fair range for \(\mathfrak u\): it
must be weakly dominant:
Let’s look at another example; this is discussed in Chapter 9 of Knapp-Vogan,
“Cohomological Induction and Unitary Representations”.
Here \(G=SO(5,4)\), and \(P\) is the unique \(\theta\)-stable parabolic with Levi factor \(U(2,2)\):
We can construct the good \(A_{\mathfrak q}(\lambda)\) at infinitesimal
character \(\rho\) using the two methods learned; let’s do that, just to
check and confirm:
If we now move to the edge of the weakly fair range, Knapp/Vogan predict
that the module will be reducible. The command Aq(x,lam,lamq) returns
a parameter PROVIDED that the module is irreducible and nonzero:
This weakly fair \(A_{\mathfrak q}(\lambda)\) module is indeed reducible,
with two constituents.
Similarly, if our \(A_{\mathfrak q}(\lambda)\) module is zero, the
command Aq(x,lam,lamq) will return an error message. Here is an
example in \(Sp(4,\mathbb R)\):
The parabolic has compact Levi factor, and the module is zero because
there is a compact simple root that is orthogonal to \(\lambda\). In
this case as well, the command Aq_reducible yields a nicer answer: